通义千问数学模型Qwen-Math_大模型服务平台百炼(Model Studio)-阿里云帮助中心

通义千问数学模型是专门用于数学解题的语言模型，致力于解决复杂、具有挑战性的数学问题。

此模型目前主要支持英语，后续将推出中英双语版本。

模型概览

商业版

模型名称	上下文长度	最大输入	最大输出	输入成本	输出成本	免费额度
模型名称	（Token数）			（每千Token）		免费额度
qwen-math-plus	4,096	3,072	3,072	0.004元	0.012元	100万Token 有效期：百炼开通后180天内
qwen-math-plus-latest				0.004元	0.012元
qwen-math-plus-0919				0.004元	0.012元
qwen-math-plus-0816				0.004元	0.012元
qwen-math-turbo				0.002元	0.006元
qwen-math-turbo-latest				0.002元	0.006元
qwen-math-turbo-0919				0.002元	0.006元

开源版

模型名称	上下文长度	最大输入	最大输出	输入成本	输出成本	免费额度
	（Token数）			（每千Token）
qwen2.5-math-72b-instruct	4,096	3,072	3,072	0.004元	0.012元	100万Token 有效期：百炼开通后180天内
qwen2.5-math-7b-instruct				0.001元	0.002元
qwen2.5-math-1.5b-instruct				限时免费
qwen2-math-72b-instruct				0.004元	0.012元
qwen2-math-7b-instruct				0.001元	0.002元
qwen2-math-1.5b-instruct				目前仅供免费体验。免费额度用完后不可调用，敬请关注后续动态。

qwen-math-plus-latest、qwen-math-plus-0919、qwen-math-turbo、qwen-math-turbo-latest、qwen-math-turbo-0919、qwen2.5-math模型的默认System Message为"Please reason step by step, and put your final answer within \\\\boxed{}."。

关于模型的限流条件，请参见限流。

示例代码

您需要已获取API Key并配置API Key到环境变量。如果通过OpenAI SDK或DashScope SDK进行调用，还需要安装SDK。

通义千问数学模型擅长解决英文数学类问题，在您的输入问题中请使用LaTex表示数学符号或公式，如：

$x$ 表示数学符号
$4x+5 = 6x+7$ 表示数学公式

此处以一元一次方程为例，向您展示通过OpenAI或者DashScope的方式体验通义千问数学模型在数学问题上的能力。

OpenAI兼容

您可以通过OpenAI SDK或OpenAI兼容的HTTP方式调用通义千问数学模型。

Python

示例代码

from openai import OpenAI
import os

def get_response():
    client = OpenAI(
        api_key=os.getenv("DASHSCOPE_API_KEY"), # 如果您没有配置环境变量，请在此处用您的API Key进行替换
        base_url="https://dashscope.aliyuncs.com/compatible-mode/v1",  # 填写DashScope服务的base_url
    )
    completion = client.chat.completions.create(
        model="qwen2-math-72b-instruct",
        messages=[
            {'role': 'system', 'content': 'You are a helpful assistant.'},
            {'role': 'user', 'content': 'Find the value of $x$ that satisfies the equation $4x+5 = 6x+7$.'}]
        )
    print(completion.model_dump_json())

if __name__ == '__main__':
    get_response()

返回结果

{
  "id": "chatcmpl-3ddf85f7-71c1-9fef-9c95-22671565895a",
  "choices": [
    {
      "finish_reason": "stop",
      "index": 0,
      "logprobs": null,
      "message": {
        "content": "To solve the equation \\(4x + 5 = 6x + 7\\), we will follow a step-by-step approach to isolate the variable \\(x\\).\n\n1. **Start with the given equation:**\n   \\[\n   4x + 5 = 6x + 7\n   \\]\n\n2. **Subtract \\(4x\\) from both sides to eliminate \\(x\\) from the left side:**\n   \\[\n   4x + 5 - 4x = 6x + 7 - 4x\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   5 = 2x + 7\n   \\]\n\n3. **Subtract 7 from both sides to isolate the term with \\(x\\) on the right side:**\n   \\[\n   5 - 7 = 2x + 7 - 7\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -2 = 2x\n   \\]\n\n4. **Divide both sides by 2 to solve for \\(x\\):**\n   \\[\n   \\frac{-2}{2} = \\frac{2x}{2}\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -1 = x\n   \\]\n\n5. **Write the final answer:**\n   \\[\n   \\boxed{-1}\n   \\]\n\nThus, the value of \\(x\\) that satisfies the equation \\(4x + 5 = 6x + 7\\) is \\(\\boxed{-1}\\).",
        "refusal": null,
        "role": "assistant",
        "function_call": null,
        "tool_calls": null
      }
    }
  ],
  "created": 1724068397,
  "model": "qwen2-math-72b-instruct",
  "object": "chat.completion",
  "service_tier": null,
  "system_fingerprint": null,
  "usage": {
    "completion_tokens": 331,
    "prompt_tokens": 42,
    "total_tokens": 373
  }
}

curl

示例代码

curl --location "https://dashscope.aliyuncs.com/compatible-mode/v1/chat/completions" \
--header "Authorization: Bearer $DASHSCOPE_API_KEY" \
--header "Content-Type: application/json" \
--data '{
    "model": "qwen2-math-72b-instruct",
    "messages": [
        {
            "role": "system",
            "content": "You are a helpful assistant."
        },
        {
            "role": "user", 
            "content": "Find the value of $x$ that satisfies the equation $4x+5 = 6x+7$."
        }
    ]
}'

返回结果

{
  "choices": [
    {
      "message": {
        "role": "assistant",
        "content": "To solve the equation \\(4x + 5 = 6x + 7\\), we will follow a step-by-step approach to isolate the variable \\(x\\).\n\n1. **Start with the given equation:**\n   \\[\n   4x + 5 = 6x + 7\n   \\]\n\n2. **Subtract \\(4x\\) from both sides to eliminate \\(x\\) from the left side:**\n   \\[\n   4x + 5 - 4x = 6x + 7 - 4x\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   5 = 2x + 7\n   \\]\n\n3. **Subtract 7 from both sides to isolate the term with \\(x\\) on the right side:**\n   \\[\n   5 - 7 = 2x + 7 - 7\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -2 = 2x\n   \\]\n\n4. **Divide both sides by 2 to solve for \\(x\\):**\n   \\[\n   \\frac{-2}{2} = \\frac{2x}{2}\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -1 = x\n   \\]\n\n5. **Write the final answer:**\n   \\[\n   \\boxed{-1}\n   \\]\n\nThus, the value of \\(x\\) that satisfies the equation \\(4x + 5 = 6x + 7\\) is \\(\\boxed{-1}\\)."
      },
      "finish_reason": "stop",
      "index": 0,
      "logprobs": null
    }
  ],
  "object": "chat.completion",
  "usage": {
    "prompt_tokens": 42,
    "completion_tokens": 331,
    "total_tokens": 373
  },
  "created": 1724068476,
  "system_fingerprint": null,
  "model": "qwen2-math-72b-instruct",
  "id": "chatcmpl-dc1cca46-dbe1-9543-a3fe-f0db8d05141e"
}

DashScope

您可以通过DashScope SDK或HTTP方式调用通义千问模型，体验单轮对话的功能。

Python

示例代码

import random
from http import HTTPStatus
import dashscope


def call_with_messages():
    messages = [
        {'role': 'user', 'content': 'Find the value of $x$ that satisfies the equation $4x+5 = 6x+7$.'}]
    response = dashscope.Generation.call(
        model='qwen2-math-72b-instruct',
        messages=messages,
        # 设置result_format为message格式
        result_format='message',  
    )
    if response.status_code == HTTPStatus.OK:
        print(response)
    else:
        print('Request id: %s, Status code: %s, error code: %s, error message: %s' % (
            response.request_id, response.status_code,
            response.code, response.message
        ))


if __name__ == '__main__':
    call_with_messages()

返回结果

{
  "status_code": 200,
  "request_id": "021f9c99-fcc6-9a48-847f-45d9db78ea65",
  "code": "",
  "message": "",
  "output": {
    "text": null,
    "finish_reason": null,
    "choices": [
      {
        "finish_reason": "stop",
        "message": {
          "role": "assistant",
          "content": "To solve the equation \\(4x + 5 = 6x + 7\\), we will follow a step-by-step approach to isolate the variable \\(x\\).\n\n1. **Start with the given equation:**\n   \\[\n   4x + 5 = 6x + 7\n   \\]\n\n2. **Subtract \\(4x\\) from both sides to eliminate \\(x\\) from the left side:**\n   \\[\n   4x + 5 - 4x = 6x + 7 - 4x\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   5 = 2x + 7\n   \\]\n\n3. **Subtract 7 from both sides to isolate the term with \\(x\\) on the right side:**\n   \\[\n   5 - 7 = 2x + 7 - 7\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -2 = 2x\n   \\]\n\n4. **Divide both sides by 2 to solve for \\(x\\):**\n   \\[\n   \\frac{-2}{2} = \\frac{2x}{2}\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -1 = x\n   \\]\n\n5. **Write the final answer:**\n   \\[\n   \\boxed{-1}\n   \\]\n\nThus, the value of \\(x\\) that satisfies the equation \\(4x + 5 = 6x + 7\\) is \\(\\boxed{-1}\\)."
        }
      }
    ]
  },
  "usage": {
    "input_tokens": 31,
    "output_tokens": 331,
    "total_tokens": 362
  }
}

Java

示例代码

// Copyright (c) Alibaba, Inc. and its affiliates.

import java.util.Arrays;
import com.alibaba.dashscope.aigc.generation.Generation;
import com.alibaba.dashscope.aigc.generation.GenerationResult;
import com.alibaba.dashscope.aigc.generation.models.QwenParam;
import com.alibaba.dashscope.common.Message;
import com.alibaba.dashscope.common.Role;
import com.alibaba.dashscope.exception.ApiException;
import com.alibaba.dashscope.exception.InputRequiredException;
import com.alibaba.dashscope.exception.NoApiKeyException;

public class Main {
    public static void callWithMessage()
            throws NoApiKeyException, ApiException, InputRequiredException {
        Generation gen = new Generation();
        Message userMsg = Message.builder().role(Role.USER.getValue()).content("Find the value of $x$ that satisfies the equation $4x+5 = 6x+7$.").build();
        QwenParam param =
                QwenParam.builder().model("qwen2-math-72b-instruct").messages(Arrays.asList(userMsg))
                        .resultFormat(QwenParam.ResultFormat.MESSAGE)
                        .build();
        GenerationResult result = gen.call(param);
        System.out.println(result);
    }


    public static void main(String[] args){
        try {
            callWithMessage();
        } catch (ApiException | NoApiKeyException | InputRequiredException e) {
            System.out.println(e.getMessage());
        }
        System.exit(0);
    }
}

返回结果

{
  "requestId": "a9f3d0b9-41b0-9d49-8cb0-158974a1bdae",
  "usage": {
    "input_tokens": 31,
    "output_tokens": 331,
    "total_tokens": 362
  },
  "output": {
    "choices": [
      {
        "finish_reason": "stop",
        "message": {
          "role": "assistant",
          "content": "To solve the equation \\(4x + 5 = 6x + 7\\), we will follow a step-by-step approach to isolate the variable \\(x\\).\n\n1. **Start with the given equation:**\n   \\[\n   4x + 5 = 6x + 7\n   \\]\n\n2. **Subtract \\(4x\\) from both sides to eliminate \\(x\\) from the left side:**\n   \\[\n   4x + 5 - 4x = 6x + 7 - 4x\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   5 = 2x + 7\n   \\]\n\n3. **Subtract 7 from both sides to isolate the term with \\(x\\) on the right side:**\n   \\[\n   5 - 7 = 2x + 7 - 7\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -2 = 2x\n   \\]\n\n4. **Divide both sides by 2 to solve for \\(x\\):**\n   \\[\n   \\frac{-2}{2} = \\frac{2x}{2}\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -1 = x\n   \\]\n\n5. **Write the final answer:**\n   \\[\n   \\boxed{-1}\n   \\]\n\nThus, the value of \\(x\\) that satisfies the equation \\(4x + 5 = 6x + 7\\) is \\(\\boxed{-1}\\)."
        }
      }
    ]
  }
}

curl

示例代码

curl --location "https://dashscope.aliyuncs.com/api/v1/services/aigc/text-generation/generation" \
--header "Authorization: Bearer $DASHSCOPE_API_KEY" \
--header "Content-Type: application/json" \
--data '{
    "model": "qwen2-math-72b-instruct",
    "input":{
        "messages":[      
            {
                "role": "system",
                "content": "You are a helpful assistant."
            },
            {
                "role": "user",
                "content": "Find the value of $x$ that satisfies the equation $4x+5 = 6x+7$."
            }
        ]
    },
    "parameters": {
        "result_format": "message"
    }
}'

返回结果

{
  "output": {
    "choices": [
      {
        "finish_reason": "stop",
        "message": {
          "role": "assistant",
          "content": "To solve the equation \\(4x + 5 = 6x + 7\\), we will follow a step-by-step approach to isolate the variable \\(x\\).\n\n1. **Start with the given equation:**\n   \\[\n   4x + 5 = 6x + 7\n   \\]\n\n2. **Subtract \\(4x\\) from both sides to eliminate \\(x\\) from the left side:**\n   \\[\n   4x + 5 - 4x = 6x + 7 - 4x\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   5 = 2x + 7\n   \\]\n\n3. **Subtract 7 from both sides to isolate the term with \\(x\\) on the right side:**\n   \\[\n   5 - 7 = 2x + 7 - 7\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -2 = 2x\n   \\]\n\n4. **Divide both sides by 2 to solve for \\(x\\):**\n   \\[\n   \\frac{-2}{2} = \\frac{2x}{2}\n   \\]\n   Simplifying both sides, we get:\n   \\[\n   -1 = x\n   \\]\n\n5. **Write the final answer:**\n   \\[\n   \\boxed{-1}\n   \\]\n\nThus, the value of \\(x\\) that satisfies the equation \\(4x + 5 = 6x + 7\\) is \\(\\boxed{-1}\\)."
        }
      }
    ]
  },
  "usage": {
    "total_tokens": 373,
    "output_tokens": 331,
    "input_tokens": 42
  },
  "request_id": "ec5d01f6-3b78-95f2-a300-d01a601bacdf"
}

常见问题

如何利用通义千问数学模型解答图片中的数学问题？

通义千问数学模型暂不支持图片识别功能。

如果图片中是简单的数学问题，可以使用通义千问VL模型进行解答。
如果图片中包含复杂的数学问题，可以先使用通义千问VL模型提取图片中的文字，再使用通义千问数学模型解答问题。

API参考

关于通义千问数学模型的输入与输出参数，请参考通义千问。